Task: Given two arrays A and B of size N and M respectively. Sort the array A based on elements in B. If A elements not present in B then append them at the end in sorted order. Example: Input: 1 11 4 2 1 2 5 7 1 9 3 6 8 8 2 1 8 3 Output: 2 2 1 1 8 8 3 5 6 7 9 Here is the Code: Program in C++: #include<iostream> #include<bits/stdc++.h> using namespace std; int main() { int t; cin>>t; while(t--) { int n,m; cin>>n>>m; int a[n],b[m]; map<int,int> rs; for(int i=0;i<n;i++) { cin>>a[i]; rs[a[i]]++; } for(int i=0;i<m;i++) { cin>>b[i]; if(rs.find(b[i])!=rs.end()) { int t = rs[b[i]]; while(t!=0) { cout<<b[i]<<" "; t--; } rs.erase(b[i]); } } for(auto i=rs.begin();i!=rs.end();i++)